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When I used Maple to solve 3 constants in 3 integral equations, fsolve cannot give me the numerial solutions. It copied the equations and showed me “fsolve（......）”. But if I change the positions of 2terms in the equations (for example a+b is rewritten as b+a), fsolve can give me the numerical solutions for the 3 constants. 

In most cases, I donot know the right order and it cannot give me the results. So what is the problem?...

Hello,

I'm trying to fit a double-diode equation using Maple.  I can get an analytic form of the fitting function in my two variables V and J of the form V(J), but I want J(V), so I'm using fsolve to extract this.  I'm then trying to fit the resulting function to a set of experimental data, but I'm getting an error about writing to an rtable.  I've tested the function, and it gives me a numeric value if I give it numeric inputs.  Is there a way I can fit it?  Code is below:

Hello, 

I am fairly new to using Maple and am a university student. Bascially, I wanted to ask, how can I solve for all roots of the transcendental equation 

=

I am having trouble identifying all the possible roots existing in the range specified.

In the file attached i have a non-linear set of equations that are solved for "w" value specified...but fsolve provides solutions only at certain values of "w" , does it mean there is no solution for other data points ?...or is there a way to find out all possible solutions for each value of "w"

Question_primes.mw

fsolve_test.mw fsolve test

Can Maple 13 solve nonlinear algebraic equations system numerically without using fsolve? for example Gauss siedel iterative method .

Why

fsolve((a^2-1)/a, fulldigits, -4..4, a=9.0)

say that ' a=9.0' is invalid range?

P.S. If answer exist it also should work with avoid option.

P.P.S. Arguments processing of fsolve is terrible. After formatting and trying to understand eval(fsolve) my brain blows up. Why maple has no universal argument processing utilite avoiding dozenz of 'ifs'?

Daer all! I want to solve the following equation

> H(z)*(1-m*H(0)^2*(1+z)^3/H(z)^2)-2*e*sqrt(1-c^2)*sqrt(r)*H(0) = 0;

where H(0) denotes the value of H(z) at z=0 and other constants are

> m := 0.211: c := 0.80: r := 0.338: e := 1:

If I want to use the fsolve command as

> eq := z->H*(1-m*H(0)^2*(1+z)^3/H^2)-2*e*sqrt(1-c^2)*sqrt(r)*H(0) = 0;

> Y := z-> fsolve(eq(z), H=1):  

what should I imply instead of H(0)? 

Dear guys! I have an equation as

> eq := z-> H*(1-m*h^2*H^(-2)*(1+z)^(3))-2*e*sqrt(1-c^2)*sqrt(r)*h=0:

where

> m := 0.211: h := 0.741: c := 0.80: r := 0.338: e := 1:

At this equation H is an unknown function of z, h is the value of H at z=0 and I want to obtain H(z) actually(for example the graph of H(z) for z=-1..5). So I did as following

> Y := z-> fsolve(eq(z), H=h):    **

plot(eval(H, H='Y(z)'), z=-1 .. 5);

Why does fsolve miss some solutions?  For instance fsolve(sqrt(x²+4x-3)=-1+2x,x) only finds solution x=2, whereas x=2/3 is also a solution.

Ratch

The fsolve in the attached code took 45.615 sec to execute. For Delta >= 0.15 the execution time was only about 0.5 sec. For Delta = 0.12 and Delta = 0.11 the execution times were about 400 and 600 sec, respectively. Why does the execution time increase with orders of magnitude when I decrease Delta? And how can I speed up the process? Henning

I have two equations with weierstrass functions and got problem with fsolve: 

f1:=WeierstassZeta(z1-z2,0.1,2.)+z1=0:

f2:=WeierstrassZeta(z2-z1,0.1,2.)+z2=0:

fsolve({f1,f2});

results are like Weierstrass (z1-z2,....) which are not simplified even I add 'simplify' in fsolve. I want the values of z1 and z2 explicitly, i.e. z1= ,z2 . How can I fix this. Please help.

Thanks

Hi,

I have to solve a very complex trigonometric equation which has 0,1 or 2 solutions between 0 and Pi (it depends from some parameters...).

The first problem I solved is to find the two solutions (when they exist), because at the beginning, the fsolve function returned only one solution. So, reading in your site, I solved this problem "splitting" che solutions domain in two parts in which I expect to find the two different solutions.

So for example a I wrote:

Hi,

How to solve this equation?

Any Idea?

Thx

1.778895759*Sigma-1831241.099/(76553.66445-.576e-5*Sigma^2)+6600.970252*Sigma/(76553.66445-.576e-5*Sigma^2)+.5739576533e-1*Sigma^2/(76553.66445-.576e-5*Sigma^2)+.4735119433e-4*exp(.7618258041e-2*Sigma)*Sigma^2/exp(.9051395693e-5*Sigma)/(76553.66445-.576e-5*Sigma^2)-39332.76308*exp(.7618258041e-2*Sigma)*(41.17+1/(1-exp(-160)))/exp(.9051395693e-5*Sigma)/(-69.17083220+Sigma)/(-69.17083220-Sigma)-629324.2088*exp(.7618258041e-2*Sigma...

Hey everybody,

for some reason I dont get for the following problem any answer, with other data it worked, but not whit this!? and i know that there is a intersection point!!

> S1 := proc (t) options operator, arrow; F[1](t)*m[1]*(1-F[2](t)) end proc;
> S2 := proc (t) options operator, arrow; F[2](t)*(m[2]+F[1](t)*m[1]) end proc;
> F[1] := proc (t) options operator, arrow; (1-exp(-(p[1]+q[1])*t))/(1+q[1]*exp(-(p[1]+q[1])*t)/p[1]) end proc;