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underline is a simple procedure:
> s := solve({5*A+3*B = 5, 8*A-9*B = 94}, [A, B]);
s := [[A = 109/23, B = -430/69]]
> assign(s);
> A; B;
109/23
-430/69

But, now what I want to use is not 109/23 or -430/69, but A or B.
That is to say, firstly, I need use root of equation, so Execute Command
> assign(s);
> A; B;
then, I can apply 109/23 or -430/69. Then later on, I want to use A or B, which now are viewed asariable? Now how can I do?

Hello, 

I am fairly new to using Maple and am a university student. Bascially, I wanted to ask, how can I solve for all roots of the transcendental equation 

tan(9*(1.1575*10^12/(1-.5)^1.2-x^2)^(1/2)*10^(-6)*(1/2))/tan(9*(5.555*10^11/(1-.5)^1.2-x^2)^(1/2)*10^(-6)*(1/2))

=

I am having trouble identifying all the possible roots existing in the range specified.

In the file attached i have a non-linear set of equations that are solved for "w" value specified...but fsolve provides solutions only at certain values of "w" , does it mean there is no solution for other data points ?...or is there a way to find out all possible solutions for each value of "w"

Question_primes.mw

I have defined a function as follows:

f:=alpha->1-RombInt(10*tan(x)^alpha,0,Pi/4,1,2);

and now i need to plot this function to see where the root lies, i have tried to do this using the following command:

plot(10*tan(x)^alpha);

and i have tried putting in boundaries but it doesnt seem to work. Can anyone help me please. 

Dear Primers

I have an exponantial equation of the form below:

eq161 := 1/2*alpha^4*(-2*exp(-1+1/2*(4*alpha^2+1)^(1/2)+1/2*(-4*alpha^2+1)^(1/2))*(4*alpha^2+1)^(1/2)+2*exp(-1+1/2*(4*alpha^2+1)^(1/2)-1/2*(-4*alpha^2+1)^(1/2))*(4*alpha^2+1)^(1/2)-2*exp(-1+1/2*(4*alpha^2+1)^(1/2)-1/2*(-4*alpha^2+1)^(1/2))*(-4*alpha^2+1)^(1/2)+2*exp(-1-1/2*(-4*alpha^2+1)^(1/2)-1/2*(4*alpha^2+1)^(1/2))*(-4*alpha^2+1)^(1/2)+2*exp(-1+1/2*(-4*alpha^2+1)^(1/2)-1/2*(4*alpha^2+1)^(1/2)...

When i try to get all roots for an ODE, i try to use fsolve:

  fsolve((rhs(ODE_4))(t)=0,t=10..20);

where ODE_4 is an ODE (dsolve, numeric, output=listprocedure), where i want to find the root of the 4th variable in the ODE (4 should be an index).

Then i only get the fist root after t=10 and the computation stops. What can i do to get ALL roots in the given interval?

Dear Friends:

My original equation is

solve({(1-3*q2)*(1+lamda) = 0, r1*q1-2*r2*XA*(1+lamda) = 0, (1-2*q2)*q2-r2*XA^2 = 0, 1-3*q1+r1*XA = 0}, {XA, q1, q2, lamda})

The answer is

{XA = -1/r1, q1 = 0, q2 = RootOf(r2-r1*_Z+2*_Z^2)/r1, lamda = -1}, {XA = RootOf(-1+9*r2*_Z^2), q1 = 1/3+(1/3)*r1*RootOf(-1+9*r2*_Z^2), q2 = 1/3, lamda = (1/6)*(9*r2*r1*RootOf(-1+9*r2*_Z^2)+r1^2-6*r2)/r2}

 

Two questions:

1. Actually I want...

how to solve

-x^8*a^4+48*z^4+48*x^7*a+8*z*x^6*a-1 = 0


for a

i tried

 

solve(-x^8*a^4+48*z^4+48*x^7*a+8*z*x^6*a-1 = 0, a)

 

and got

 

Dear Sir / Madam,
Could you recommend me how to find the square root of the complex equation correctly?
My equation looks like this
sqrt(complex_equation_1^2 + complex_equation_2^2).

AHOY! when I compute the cube root of -8 using maple  14.  It gives me the output -8^(1/3)

my input was........

f:=x->x^(1/3)

f(-8)

I would like maple to give me the answer of -2 How do I change that? Note I need to define the cube root as a function.

Thanks

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