AHSAN

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5 years, 143 days

MaplePrimes Activity


These are replies submitted by AHSAN

Thank you sir.  The problem is that I do not know the exact policy of this plate form and I admit this is the little repeated question but it contains a new problem that I am facing. i do not receive any message can you please share it again with me@acer 

Can you please upload the maple file for above mentioned method and problem@Carl Love 

@Ronan  I am interested to find expression between Q and all other involved value after putting T=0. can you please upload maple file

@Carl Love  value of h=1+x^2/2 and then we replace x by x sub s. all other parameters like A, D,a1 etc are constant and take any value of its.

Dear sir thanks alot for your help out. @tomleslie 

sorry for wasting your time now it final valve of  x =1,0,-2,-3,-4 aginst I want to plot F@Carl Love 

@Carl Love i want to use the value of x =1,0,-2,-3,-4

how to the fixed the axis in the above command, i.e x=-5..3 and can you plesae purposeof this 

view= [0..nops(F)+0.5, 0..1.2*max(F)

 @Carl Love 

pls have look on my attaced maple file. I want to mention legends in the graph but failed. I tried your method pls correct me where I am dosing wrong. The original picture and the method I followed are mention at the end of the same maple file. i want to mention only one two legend k and Q in  the
 

restart

A := beta*(-60*lambda*(1+(1/2)*x^2)^4+(-63*k^3+99*k^2-99*k+63)*(1+(1/2)*x^2)^3-288*Q*(k^2-(11/8)*k+1)*(1+(1/2)*x^2)^2-486*Q^2*(k-1)*(1+(1/2)*x^2)-324*Q^3)/(20*(1+(1/2)*x^2)^7)-(3*(k*(1+(1/2)*x^2)+2*Q-1-(1/2)*x^2))/(2*(1+(1/2)*x^2)^3)

(1/20)*beta*(-60*lambda*(1+(1/2)*x^2)^4+(-63*k^3+99*k^2-99*k+63)*(1+(1/2)*x^2)^3-288*Q*(k^2-(11/8)*k+1)*(1+(1/2)*x^2)^2-486*Q^2*(k-1)*(1+(1/2)*x^2)-324*Q^3)/(1+(1/2)*x^2)^7-(3/2)*(k*(1+(1/2)*x^2)+2*Q-1-(1/2)*x^2)/(1+(1/2)*x^2)^3

(1)

opt1 := "β=0.1,Q=0.5516,λ=-0.0396,k=0.1"; opt2 := "β=0.2,Q=0.4903,λ=-0.0411,k=0.2"

opt3 := "β=0.3,Q=0.4290,λ=-0.0419,k=0.3"; opt4 := "β=0.4,Q=0.3677,λ=-0.0417,k=0.4"

opt5 := "β=0.4,Q=0.3677,λ=-0.0417,k=0.4"

N := plot([eval(A, [parse(opt1)]), eval(A, [parse(opt2)]), eval(A, [parse(opt3)]), eval(A, [parse(opt4)]), eval(A, [parse(opt5)])], x = -2 .. 2, color = [red, blue], thickness = 2)

Error, incorrect syntax in parse: `;` unexpected (near 6th character of parsed string)

 

B := plot([5.2, 4.7], x = -.9 .. -.4, color = [red, blue], thickness = 3)

T := plots:-textplot([[-2.9, 5.2, opt1], [-3.2, 4.7, opt2], [-3.2, 4.7, opt3], [-3.2, 4.7, opt2], [-3.2, 4.7, opt4], [-3.2, 4.7, opt5]], font = [times, 16], align = right)

plots:-display(N, B, T, scaling = constrained, size = [600, 500])

Error, (in plots:-display) expecting plot structure but received: N

 

NULL

NULL

NULL

NULL

plot([subs(beta = .1, Q = .5516, lambda = -0.396e-1, k = .1, A), subs(beta = .2, Q = .4903, lambda = -0.411e-1, k = .2, A), subs(beta = .3, Q = .4290, lambda = -0.419e-1, k = .3, A), subs(beta = .4, Q = .3677, lambda = -0.417e-1, k = .4, A)], x = -5 .. 5, colour = [black, red, blue, green, purple])

 

``


 

Download help_graph.mw

graph @Kitonum 

Thank you for your help. i used this command but I want to show inside the graph, also when I select the top or right side the picture become more compress which is not looked good. I want to draw like I posted the picture@Kitonum 

Thank you for your help out. can you please guide me on how to mention the lambda horizontally and t vertically@acer 

 can you please upload maple file with example @Madhukesh J K 

@rlopez sir can you ls upload your maple file with the newton method that you did.

@acer basically this problem is related to my research. i want to mention the name of method that we used to compute the valve of lambda. so can you pls mention the name of the method that you used to obtain the valve of lambda

@acer

can you pls explain it little. and why you are taking digits 16? what does it means and is it possible to solve with regula falsi position method 

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