emendes

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9 years, 283 days

MaplePrimes Activity


These are replies submitted by emendes

@Carl Love Thanks.   The extra messages are data type, order and etc.   Although I no longer use Vector or vector, I wonder whether why Maple returns lot of stuff when issuing the command Vector[row]([x1*x2-u0,x1*x1+x2]) inside a proc.   Odd enough, when I restarted maple, the extra stuff did not show up.

As for the HelpTools, many thanks.  I will try searching the web to see if there is an example of building a package with help files from scratch.  Fortunately Maple 18 has the HelpTools.

 

@emendes Thank you all for all the help and patience.   I managed to get rid of all vectors and Vectors and now the code is free from calling extra packages (inner is needed though but a solution is already given). 

As a final question I wonder if you could give some pointers on how to write a help file for the procs.   Thank you!

@Carl Love If that is the case, how can I avoid the extra messages that comes with Vector?   The extra messages wreck the old function.   linalg[vector] does not return such messages and therefore it works fine.

@Carl Love Thank you. I have changed the code to use numelems.  I am not sure of anything since the code is 24 years old.  I don't even know if using vector is necessary.  Perhaps list will do the job.  The only thing I need is to calculate the dotproduct (and inner works with list) and the Lie derivative.  I am moving one step at the time and in doing so I hope I will remember how to use Maple.

@emendes LinearAlgebra[ColumnDimension](f) does the trick since all the vectors are defined with Row.  

@emendes  Sorry, I am mistaken, nops cannot be used in this case.

@Kitonum Thank you ever so much.  I have added interface(rtablesize=infinity): inside the main proc.  It worked but I am not sure if that is the right thing to do, is it?

 

In the old code linalg[vectdim](f) returned f's dimension.  I could not find anything similar in LinearAlgebra but nops(f) seems to work.  Would nops be ok?

Now that my old code is working I am trying to convert all deprecated functions to new ones.   The first setp was changing vector to Vector[row]. 

When trying to convert a list to Vector inside a proc, the outcome comes with a lot of info that wrecks the code.  Example:

aux:=[-x1*x2+u0,x1*x1-2*x2,u1,u2,u3,u4,u5,u6,u7,u8,u9,u10];

f:=Vector[row](aux);

f returns [1..12 Vector rwo, Data Type: anything, ..., Order: fortran_order].   How to get a simple output as vector did?

Many thanks

Ed

 

 

@Carl Love Many many thanks.   Part of the old code is now working.   

@Carl Love Yes, but I found that there is nothing but (x,y) -> x-y.  At least it works for the cases I have tried. Many thanks.

@Carl Love Many thanks.  Would inner always be available?

@Kitonum Thank you ever so much.   There is another function that I could find in the version.  Here is an example:

 

(anglebracket(X-Y))(y2, -(-x1*x2+u0)*x2-(x1^2-2*x2)*x1+u1)

 

Unfortunately I don't have a foggiest idea where this function comes from.

 

I would rather not use LinearAlgebra right now.  If I do I have changing all the definitions from vector to Vector. Once I get the code working I will definitely change it.  Many thanks.

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