salim-barzani

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1 years, 44 days

MaplePrimes Activity


These are replies submitted by salim-barzani

@dharr first thanks for this code
there is one case missing which is A  and B not equal to zero !
also i am  looking for U(xi) with telling me when for example A=0  then U(xi)=@  with substitute case in U(xi), also i need to clarify the odetes, i know it is work but want be sure for substitute odetest must be zero,  i am sure you didn't see this file i upload later 

i hope undrestand my mean

all_case.mw

@Kitonum it seems you have a good expreince in changing variable always i have problem in physic how we can remove the absolute value automatically i do that by hand in equation where  q=U(x)exp(I*x) then |q|=U(x) and |q|^2=U(x)^2 how maple do that automatically and do the change variable all by programing something like that in below picture also i have esier   if needed i just want to know how  replace this absolute value and do that automatically without need hand 

@acer  it is imposible for each equation i do the that i must update version i hope that is work 

@acer i saw you use kernelopts but now work my maple is like that back to orginal


 

restart

kernelopts(version)

`Maple 2021.0, X86 64 WINDOWS, Mar 5 2021, Build ID 1523359`

(1)

M := sin(x)/cos(x)

sin(x)/cos(x)

(2)

simplify(M)

sin(x)/cos(x)

(3)

K := 1/sinh(x)

1/sinh(x)

(4)

simplify(K)

1/sinh(x)

(5)

Q := sqrt(beta[0]/(B[1]*cosh(xi*sqrt(-lambda))))

(beta[0]/(B[1]*cosh(xi*(-lambda)^(1/2))))^(1/2)

(6)

simplify(Q)

(beta[0]/(B[1]*cosh(xi*(-lambda)^(1/2))))^(1/2)

(7)

simplify(Q, trig)

(beta[0]/(B[1]*cosh(xi*(-lambda)^(1/2))))^(1/2)

(8)

NULL

NULL

NULL

NULL

it is same when i apply
 

Download identity_change_M2024(1)12.mw

@nm thank you for this new code

@acer  sorry for late, if i use 2024 version this problem will be fix? and my code of 2021 is work or not?  becuase i have a lot of this problem i can't use this code to all my function the editore of journals   give us comment which we must change all of this outcomes to shorter and i must change all my outcomes it take a 2 or 3 day to change all of them.

@acer thank you so much

@acer i have the problem with your last exploring graph  please help for upgrading it  i will send you in email if possible ...

@nm thank you so much

@Kitonum i know  i have a code with it different from up but  i need more technique if have any code please share it, lets see something strange

@janhardo this code emazing and this is first time i saw 3 code horizontally together work , i think it will be more complex if i give my long equation to this i will try thanks this code is so good i liked so much.

@dharr tahnk you dear Dr.
and also C_R 2607  thanks a lot .

@C_R  yes of curse if h[1] and h[7] are zero the pde will satisfy but in that cas i find the condition c[2] he it told me it can be other than this but i don't know why is not equal to zero when i put c[2] is like that

NULL

condition1 := simplify((2*k*mu*c[1]*h[2]+2*k*mu*c[1]*h[4]-2*k*mu*c[1]*h[5]-k*c[2]*h[8]-k*c[2]*h[9])/k) = 0

2*c[1]*(h[2]+h[4]-h[5])*mu-(h[8]+h[9])*c[2] = 0

(1)

ccondition21 := simplify((-4*k*mu^3*c[1]*h[1]+3*k*mu^2*c[2]*h[7]+2*a*k*mu+k*v)/k) = 0

-4*mu^3*c[1]*h[1]+3*mu^2*c[2]*h[7]+2*a*mu+v = 0

(2)

condition2 := v = 4*mu^3*c[1]*h[1]-3*mu^2*c[2]*h[7]-2*a*mu

v = 4*mu^3*c[1]*h[1]-3*mu^2*c[2]*h[7]-2*a*mu

(3)

condition3 := 4*mu*c[1]*h[1]-c[2]*h[7] = 0

4*mu*c[1]*h[1]-c[2]*h[7] = 0

(4)

solve(condition3, c[2])

4*mu*c[1]*h[1]/h[7]

(5)

solve(condition2, v)

4*mu^3*c[1]*h[1]-3*mu^2*c[2]*h[7]-2*a*mu

(6)

solve(condition1, h[2])

-(1/2)*(2*mu*c[1]*h[4]-2*mu*c[1]*h[5]-c[2]*h[8]-c[2]*h[9])/(c[1]*mu)

(7)

pde := k^2*((D@@2)(U))(xi)*a-U(xi)*a*mu^2+U(xi)^5*c[1]*h[6]+I*k*U(xi)^2*(D(U))(xi)*c[2]*h[8]+I*k*U(xi)^2*(D(U))(xi)*c[2]*h[9]+(4*I)*k*(D(U))(xi)*h[1]*mu^3*c[1]-(3*I)*k*(D(U))(xi)*c[2]*h[7]*mu^2-(4*I)*k^3*((D@@3)(U))(xi)*h[1]*mu*c[1]-(2*I)*k*U(xi)^2*(D(U))(xi)*c[1]*mu*h[2]-(2*I)*k*U(xi)^2*(D(U))(xi)*c[1]*mu*h[4]+(2*I)*k*U(xi)^2*(D(U))(xi)*c[1]*mu*h[5]+h[1]*((D@@4)(U))(xi)*k^4*c[1]+U(xi)^3*mu*c[2]*h[8]-U(xi)^3*mu*c[2]*h[9]+U(xi)*mu^4*c[1]*h[1]+U(xi)^3*mu^2*c[1]*h[3]-U(xi)*mu^3*c[2]*h[7]-U(xi)^3*mu^2*c[1]*h[2]-U(xi)^3*mu^2*c[1]*h[4]-U(xi)^3*mu^2*c[1]*h[5]-U(xi)*w+U(xi)^3*b+k^2*U(xi)^2*((D@@2)(U))(xi)*c[1]*h[5]+U(xi)*(D(U))(xi)^2*k^2*c[1]*h[3]+k^2*U(xi)^2*((D@@2)(U))(xi)*c[1]*h[4]+I*k^3*((D@@3)(U))(xi)*c[2]*h[7]+U(xi)*(D(U))(xi)^2*k^2*c[1]*h[2]+3*k^2*((D@@2)(U))(xi)*mu*c[2]*h[7]-(2*I)*k*(D(U))(xi)*a*mu-I*k*(D(U))(xi)*v-6*k^2*((D@@2)(U))(xi)*mu^2*c[1]*h[1] = 0

U(xi)^3*b-U(xi)*w+k^2*U(xi)^2*((D@@2)(U))(xi)*c[1]*h[4]+k^2*U(xi)^2*((D@@2)(U))(xi)*c[1]*h[5]+U(xi)*(D(U))(xi)^2*k^2*c[1]*h[2]+U(xi)*(D(U))(xi)^2*k^2*c[1]*h[3]+3*k^2*((D@@2)(U))(xi)*mu*c[2]*h[7]+I*k^3*((D@@3)(U))(xi)*c[2]*h[7]-I*k*(D(U))(xi)*v-6*k^2*((D@@2)(U))(xi)*mu^2*c[1]*h[1]+k^2*((D@@2)(U))(xi)*a+U(xi)^5*c[1]*h[6]-U(xi)*a*mu^2-(4*I)*k^3*((D@@3)(U))(xi)*h[1]*mu*c[1]+(4*I)*k*(D(U))(xi)*h[1]*mu^3*c[1]-(3*I)*k*(D(U))(xi)*c[2]*h[7]*mu^2+U(xi)*mu^4*c[1]*h[1]+U(xi)^3*mu^2*c[1]*h[3]-U(xi)*mu^3*c[2]*h[7]+h[1]*((D@@4)(U))(xi)*k^4*c[1]-U(xi)^3*mu^2*c[1]*h[2]-U(xi)^3*mu^2*c[1]*h[4]-U(xi)^3*mu^2*c[1]*h[5]+U(xi)^3*mu*c[2]*h[8]-U(xi)^3*mu*c[2]*h[9]-(2*I)*k*U(xi)^2*(D(U))(xi)*c[1]*mu*h[2]-(2*I)*k*U(xi)^2*(D(U))(xi)*c[1]*mu*h[4]+(2*I)*k*U(xi)^2*(D(U))(xi)*c[1]*mu*h[5]-(2*I)*k*(D(U))(xi)*a*mu+I*k*U(xi)^2*(D(U))(xi)*c[2]*h[8]+I*k*U(xi)^2*(D(U))(xi)*c[2]*h[9] = 0

(8)
 

NULL

Download condition.mw

@acer  really you did a big help for me,i work on my thesis at PHD i have to solve my problem by maple but for graph i need matlab, so there is a lot of thing in my thesis which i can't do it by maple for example tranformation pde to ode i do by hand then i transport in maple the other stuff i do by maple , but for graph i need a form of matlab i use template word i use that but in fact i think they called form  i have some of them in matlab which i get it by my supervisor but i need update them  i am looking for some new kind of graph which is use in solving (non-linear schrodinger equation) (NPDE)(NLSE) i must graph them with hight quality and new form  iam looking and i must find new type of graph which determine and contain all detailed like (abs,Im,Re) and desity and contour and (2D, effect time effect fractional order i want collect all of them in one graph i don't know how i can do that in matlab, i have for each one seperatly but i need a new one combine them but i don't have enouh skill in matlab to construct a form  this is my mean  i hope you undrestand and always i am apreciate about your help and owe you . if you watch this graph below i have a form like that

@mmcdara  this is good for visualization but how i can use it in article or is just for watching is so prettey but where is exactly have application ?

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