Evaluating right-hand, left-hand limits

Question:Evaluating right-hand, left-hand limits

Posted: GPY 80 Products: Maple , MaplePrimes

February 01 2015

I'm trying to get the RHL of exp1:=(2/(1+e^(-1/x)) as x->0+

and have l2:=limit(exp1,x=0,right) but that isn't giving me a value. How do I correct this?

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