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Question: Why does pdsolve behave this way?

Question:Why does pdsolve behave this way?

Rouben Rostamian 8269 Maple
series pdsolve heat
July 19 2017
1

Consider a standard initial/boundary value problem for the heat equation on the interval x ∈ [0,1]:

restart;
pde := diff(u(x,t),t) = diff(u(x,t),x,x);
ic := u(x,0) = f(x);
bc := u(0,t)=0,  u(1,t)=0;

Then
pdsolve({pde, ic, bc});
produces the expected Fourier series solution.

However, if we change the interval to x ∈ [-1,1], as in:
bc := u(-1,t)=0,  u(1,t)=0;
pdsolve({pde, ic, bc});
then Maple fails to return a solution.  Why?
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