Please help with this DTM-Pade CODE

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Question:Please help with this DTM-Pade CODE

Posted: Syed Asadullah Shah 15 Product: Maple 2016

October 11 2022

How to the find values of "A" & "B"?

$restart; Digits := 10; m := 2; F[0] := 0; M := 1; F[1] := 1; F[2] := (1/2)*A; T[0] := 0; T[1] := B; for k from 0 to m+2 do F[k+3] := (M*(k+1)*F[k+1]+sum((k-r+1)*(r+1)*F[r+1]*F[k-r+1], r = 0 .. k)-(sum((k-r+1)*(k-r+2)*F[r]*F[k-r+2], r = 0 .. k)))*factorial(k)/factorial(k+3); T[k+1] := (2*(sum((k-r+1)*F[k-r+1], r = 0 .. k))+(2*(k+2))*(k+1)*F(k+2))*factorial(k)/factorial(k+1) end do; f := 0; t := 0; for k from 0 to m do f := f+F[k]*x^k; t := t+T[k]*x^k end do; print(f); print(t); with(numapprox); pade(t, x, [2, 2]); pade(diff(f, x), x, [2, 2]); solve({limit(pade*(t, x, [2, 2]), x = infinity) = 0., limit(pade(diff(f, x), x, [2, 2]), x = infinity) = 0.}, [A, B])$

(2+4*(table( [( 0 ) = 0, ( 1 ) = 1, ( 2 ) = (1/2)*A, ( 3 ) = 1/3, ( 4 ) = (1/12)*A, ( 5 ) = 1/60+(1/120)*A^2, ( 6 ) = (1/180)*A, ( 7 ) = 1/840+(1/5040)*A^2 ] ))(k+2))*x+(1+A+6*(table( [( 0 ) = 0, ( 1 ) = 1, ( 2 ) = (1/2)*A, ( 3 ) = 1/3, ( 4 ) = (1/12)*A, ( 5 ) = 1/60+(1/120)*A^2, ( 6 ) = (1/180)*A, ( 7 ) = 1/840+(1/5040)*A^2 ] ))(k+2))*x^2

Error, (in testeq) invalid arguments

Download DTM_Pade_for_A_and_B.mw

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Question:Please help with this DTM-Pade CODE

How to the find values of "A" & "B"?

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Question: Please help with this DTM-Pade CODE

Question:Please help with this DTM-Pade CODE

How to the find values of "A" & "B"?

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