Question: Logarithm Function solution

Maple Input:
restart; with(RealDomain); log[2](x^2 - 6*x) = 3 + log[2](1 - x); Maple returns as solution
ln\x - 6 x/ ln(1 - x) ------------ = 3 + --------- ln(2) ln(2) "(->)" [[x = 2], [x = -4]]
Is the solution x = 2 correct?

Substituting x=2 into the original Function Maple returns correct: log[2](2^2 - 6*2);

undefined and log[2](1 - 2).; undefined. So x =2 should not be a solution of this function.

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