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Question: Help With Improper Integral

Question:Help With Improper Integral

dcasimir 1212
integral infinity
August 30 2005
1
This integral |A^|^2(∫)[-infinity]^infinity(e)^(-2 ax^2) ⅆx gives me the output (|A|)^2 signum((e)^((-2 ax^2))) infinity unless i put parentheses around the -2a in the exponential to look like e^-((2a)*x^2) then i get more useful output that looks like (|A|)^2 ({[[1/2 (sqrt(2) sqrt(Pi))/(sqrt(a)),` `,csgn(a)=1], [infinity,` `,otherwise]]) Please explain the signum, and csgn(a) = 1 included in both outputs and the reason for this behavior ? new to maple thanks
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