## 76 Reputation

13 years, 317 days

## An error in if statement...

Maple 2016

Dear all,

I use the following statment (without numerical values)

if        IT<20     then        IT:=IT+1

if    ZUM<(0.1)^(8);    IT=20;         else;

for i from 1 to 10   do                               YU[i]:=U[i];                  od;

for i from 2 to 9 do                           DU1:=YU[i+1]- YU[i-1];        od:

end if;

ZUM:=U[1]-YU[1];

end if;

the following error occur

where is the problem.

## How to write a the iteration code in Ma...

Maple 2016

Dears I have the following statment in Matlab

r=8;             ZUM=U(1)-YU(1);            IT=0;

for r=2:10

ZU(r)=abs(U(r)-YU(r));

if ZU(r)> ZUM

ZUM=ZU(r);

else

ZUM=ZUM;

end

end

ZUM;

while IT < 20

IT=IT+1

if ZUM < (0.1)^r

IT=20;

else

for r=1:Nx

YU(r)=U(r);

end

YU;

I need to write this statment in Maple

## understand the symbol...

Maple 2016

Hellow.
Is Maple understand the symbol f(i,j), f[i,j], f:=-->(i.j) and f_{i,j}  in the same way or in different way.

## Error in resluts...

Maple 2016

Hello,

I am working with numerical function with two indices, such as f[i,j], where i,j run over 1 to N, where N is n integer number.

The resluts stored in vector colummn for each value of j. i.e.

for each j=1,     G1:=Vector[column](N,i-->f(i,1))

for each j=2,     G2:=Vector[column](N,i-->f(i,2))

and so on.

The procedure is working for the first value j=1.

for the second value the following message appear

{--> enter Terminate, args =
{--> enter Terminate, args =
<-- exit Terminate (now in Terminate) = }
<-- exit Terminate (now at top level) = }

## an error occurred, diff received 0...

Maple 2016

Hello, I have a function defined as

g :=  (x, y)->diff(u1(x, y), x, x)+diff(u2(x, y), x, y).

I want to define another function as follows

f :=  (y) ->subs(x = 0, g(x, y)) ,

Now, when I want to calculate numerical values for the new function f(0), f(0.1), f(0.2),..... and so on. The following massage appear

Error, (in f) invalid input: diff received 0, which is not valid for its 2nd argument.

What is the problem here.

Amr

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