imparter

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9 years, 319 days

MaplePrimes Activity


These are answers submitted by imparter

restart:

ET2 := int(abs(1/(x - 2) + 0.5333 + 0.3333*x + 0.1333*x^2), x = -1 .. 1);

use evalf(ET2);

you will get positive value

I got the answer as 7.954926521

restart:
with(IntegrationTools):
A:=int(cosh(cos(2*t)), t = 0 .. 2*Pi):
evalf(A):
B:=(1/2)*(int(cosh(cos(2*t)), t = 0 .. 2*Pi) + int(cosh(-cos(2*t)), t = 0 .. 2*Pi)):
evalf(A):
evalf(B):
 

Thanks for quick response, still i can not able to display here the codes A and B graphs i,e  two plots side-by-side, each composed of three plots
 
V:=(2*x^2+2*y+gamma)*y^3:
a0:=subs(x=0.9,gamma=0,V):
a1:=subs(x=0.9,gamma=2,V):
a2:=subs(x=0.9,gamma=4,V):
 
b0:=subs(x=0.1,gamma=0,V):
b1:=subs(x=0.1,gamma=2,V):
b2:=subs(x=0.1,gamma=4,V):
 
A:=plot([a0,a1,a2], y = 0 .. 1, linestyle = [dot, dash,dot], color = [red, blue,green]);
 
B:=plot([b0,b1,b2], y = 0 .. 2, linestyle = [dot, dash,dot], color = [red, blue,green]);
display(< display(A) | display(B) >);
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