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maxburakho

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6 years, 360 days
exxonmobil
chemical process engineer
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"Some Talk of Alexander and Some of Hercules, of Hector and Lysander and Such Great Names as These, But of All the World's Brave Heroes, There Is None That Can Compare, with a Tow Row Row Row Row Row, to the British Grenadiers..."

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These are questions asked by maxburakho

how do you answer people's questions on ...

maxburakho 30 MaplePrimes
October 22 2017
1 0

how do you answer people's questions on here to get the points?

fsolve function doesnt work on a system ...

maxburakho 30 Maple
rootfinding homework
October 20 2017
1 6
equations:
x[j-1]-2x[j]+x[j+1]=0, j=3...98 where x[j] is x-sub -j
-2x[1]+x[2]=5
x[1]-2x[2]+x[3]=-4
x[98]-2x[99]+x[100]=-8
x[99]-2x[100]=13
 
I'm trying to solve them using Isaac Newton's method for numerical approximation with epsilon equal to 1e-6 such in C++ code below
 
double epsilon=1e-6;
double x=1.0;
double f=x[j-1]-2x[j]+x[j+1] j=3...98; x3-x97+x98=3;
double Df=1-2+1;
while (fabs(f)>epsilon){
cout<<x<<endl;
x-=f/Df
f=x[j-1]-2x[j]+x[j+1] j=3...98; x3-x97+x98=3;
Df=1-2+1;}
cout<<x<<endl;
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