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paulmcquad

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These are questions asked by paulmcquad

How do i get the distance and midpoint i...

paulmcquad 65 Maple 2024
geometry homework midpoint
January 13 2025
3 0

Is there an easy way to get the midpoint and distance in maple?

Thanks in advance.

Distance and Midpoint

 

 

Table 1: Key Skills

NULLdmf1 := [-3, 1]

[-3, 1]

 (1)

dmf2 := [3, 2]

[3, 2]

 (2)

dmf3 := [-2, -3]

[-2, -3]

 (3)

dmf4 := [3, -2]

[3, -2]

 (4)

dmf := [dmf1, dmf2, dmf3, dmf4]

[[-3, 1], [3, 2], [-2, -3], [3, -2]]

 (5)

plot(dmf)

  

NULL

dme1a1 := [1, 3]

[1, 3]``

 (6)

dme1a2 := [5, 6]

[5, 6]

 (7)

dme1a3 := [5, 3]

[5, 3]

 (8)

dme1 := [dme1a1, dme1a2, dme1a3]

[[1, 3], [5, 6], [5, 3]]

 (9)

plot(dme1)

  

NULL

``

NULL

NULL

NULL

NULL

NULL

NULL

NULL

Download 2.1-Distance_and_Midpoint.mw

How to solve a combined inequality?...

paulmcquad 65 Maple 2024
solve homework inequality
January 12 2025
2 0

Can maple simplify a Combined Inequality? At best it outputs imho a more complicated solution.

Thanks in Advance.

sl10 := -1 <= (3-5*x)*(1/2) and (3-5*x)*(1/2) <= 9

0 <= 5/2-(5/2)*x and -(5/2)*x <= 15/2

 (1)

The output should be:

 

-3 <= x and x <= 1


Download Combined_Inequality.mw

How to write intervals using inequality ...

paulmcquad 65 Maple 2024
homework interval inequality
January 07 2025
2 4

Is there a way to put in intervals and get the output as inequality Notation? Something like this ->

Algebraic symbol - what symbol is this?...

paulmcquad 65 Maple
complex 2dmath conjugate
December 21 2024
2 1

I don't know what that line above the question is. Thanks in Advance.

How to factor complex numbers?...

paulmcquad 65 Maple 2024
complex imaginary homework
December 21 2024
2 0

NULLComplex Numbers

 

Key Skills 11-48

NULLc11 := 2-3*i+(6+8*i)"(=)"8+5*i

c12 := 4+5*i-8+2*i"(=)"-4+7*i

c13 := -3+2*i-4+4*i"(=)"-7+6*i

c14 := 3-4*i+(3+4*i) = 6NULL

c15 := 2-5*i-8-6*i"(=)"-6-11*i

c16 := -8+4*i-2+2*i"(=)"-10+6*i

c17 := 3*(2-6*i)"(=)"6-18*i

c18 := -4*(2+8*i)"(=)"-8-32*i

NULLc19 := 2*i(2-3*i) = 2*i(2-3*i)NULL

c20 := 3*i*(-3+4*i) = 3*i*(-3+4*i)

c21 := (3-4*i)*(2+i) = (3-4*i)*(2+i)NULL

c22 := (5+3*i)*(2-i) = (5+3*i)*(2-i)

``

``

Download 1.3-Complex_Numbers_bad.mw

I'm trying to get my problems in standard form  a + bi . Questions 19 - 22 are wrong.

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