Hello everyone,

I'm new at maple.Sorry if this question asked before me, but i couldnt find it.

As i said i am new

so when I open new document (mode) at maple2015 i can do basic calculations for instance additon substraction multipicitaions. But when i want the  calculate x^2+5-3 and enter it supposed to be say to me blue line as a answer. But maple says nothing.

is there any point that i missing? 

Thank you very much all you in advance.

When I wish to perform a "save as" or "export" operation on the menu bar, how do I make Maple default to the same directory as the file is located? On one of my installations, once I select a file, the directory becomes the default "save as" or "export" directory. On my other installation, it first offers me to save to the desktop and I have to search for the subdirectory desired. (This difference occurs across many versions of Maple). Installation is Windows 10.

and how to prove this make x and y are conjugate by an element of  N?

with(GroupTheory):
with(group):
G := AlternatingGroup(3);

IsFinite(G);

GroupOrder(G);

spg := SylowSubgroup(3, G);

IsAbelian(spg);

Elements(spg);
lprint(%);

H := Subgroup(G, spg);
got error, invalid input here,

GroupTheory:-SylowSubgroup(3, module () local labels, minSupp,

maxSupp, suppSize, AtkinsonsAlgorithm, IsSimpleGroupOrder,

doDerivedSeries, doLowerCentralSeries, Intersection2,

RightCosetRepresentatives, LeftCosetRepresentatives, PRA,

`Giant?`, `Even?`, doStab1, doStab, CycleIndexMonomial;

export generator_list, n, supergroup, Sylows, pCores,

ModulePrint, ModuleDeconstruct, Generators, Orbit, Orbits,

IsTransitive, Transitivity, IsPrimitive, GroupOrder,

Elements, IsAbelian, IsElementary, IsSimple, ConjugacyClass,

ConjugacyClasses, CayleyTable, Centre, DerivedSubgroup,

IsPerfect, DerivedSeries, LowerCentralSeries, NilpotencyClass\

, IsNilpotent, doUpperCentralSeries, UpperCentralSeries,

SylowSubgroup, IsSubgroup, IsNormal, Core, NormalClosure,

Normaliser, Conjugator, AreConjugate, Centraliser,

Intersection, `intersect`, LeftCoset, RightCoset,

RightCosets, LeftCosets, Factor, RandomElement, IsAlternating\

, IsSymmetric, PCore, FittingSubgroup, FrattiniSubgroup,

MatrixRepresentation, Stabiliser, CycleIndexPolynomial,

properties; option object; end module)
Error, invalid input: GroupTheory:-Subgroup expects its 1st argument, generators, to be of type {list, set, identical(undefined)}, but received module () local labels, minSupp, maxSupp, suppSize, AtkinsonsAlgorithm, IsSimpleGroupOrder, doDerivedSeries, doLowerCentralSeries, Intersection2, RightCosetRepresentatives, LeftCosetRepresentatives, PRA, `Giant?`, `Even?`, doStab1, doStab, CycleIndexMonomial; export generator_list, n, supergroup, Sylows, pCores, ModulePrint, ModuleDeconstruct, Generators, Orbit, Orbits, IsTransitive, Transitivity, IsPrimitive, GroupOrder, Elements, IsAbelian, IsElementary, IsSimple, ConjugacyClass, ConjugacyClasses, ...

N := Normaliser(G, spg);

H2 := Subgroup(G, G);

how to find the subgroup G which is finite group here?

elist := Elements(H2);
AreConjugate(elist[1], elist[2], N);

originally x and y are not conjugate,

how to prove this make x and y are conjugate by an element of  N if spg is abelian

where x and y are elements of H2 which is subgroup of G, which is finite group

i guess find subgroup with following command, however, normaliser N can not

make elements of x and y conjugate

H2 := Subgroup(Elements(G), G);
elist := Elements(H2);
AreConjugate(elist[2], elist[3], N); #N*elist[1]*N^(-1) = elist[2]

but it is false,

i use G := AlternatingGroup(5); it is true,

does it mean that this theorem is not for all cases?

Good Morning,

This is the script that I have used to to an integration, as the command ''int'' didn't work because the coputation was really heavy.

p_old := 0;

g := 0; #index

E_tot_net_Point := 0;

for g to 2 do

 h := g+1;

 loopstart := SP_time[g];

 loopend := SP_time[h];

  for tt from loopstart by 0.01 to loopend do

   t := tt;

   P_tot_net_Fkt := t -> C_motore[g]*omega_motore[g]

if t≠SP_time[g] and t ≠ SP_time[h] then

 P_tot_net_Point := P_tot_net_Fkt(t);

 P_tot_net_Point_next := P_tot_net_Fkt(t+0.001);

 plt_P_tot_net_plt[t] := pointplot([t, P_tot_net_Point]);

 E_tot_net_Point := E_tot_net_Point+(P_tot_net_Point*0.01);

 plt_E_tot_net_plt[t] := pointplot([t, E_tot_net_Point]);

 p_old := P_tot_net_Point;

end if;      

  end do:

end do:

plots:-display(entries(plt_E_tot_net_plt, 'nolist'), title = "Energy", color = "Red", symbol = point, symbolsize = 20, gridlines = true, size = [1000, 500], labels = ['[s]', '[Watt*s]'], font = [axes, 12])


I have plotted the function as a series of points over the orizontal axis (t).

Now I would like to calculate the last value of the curve (which is itself a point) as a function of the orizontal axes t. How can I do it?

Something like E_tot_net_Point = f(t)

Thank you for the help

I want to build a custom component by the material’s stress-strain curve ,for the component signal input is the x(t)(displacement-time curve), then I can simulate the material’s acceleration-time curve，the stress-strain equation , parameter and the custom component I built has been given in the picture，but the x(t) is same as the s[rel](t),so how to solve this problem? Thanks first.

we have positive number from 1 to 1000. how many time we write number 3?

How to increase the size of toolbar icons in Maple 2015 32-bit Classic on Windows?

How do you put labels on individual columns in ColumnGraph?

a1:= f(x) :
> T1 :=simplify((taylor(a1,x=alpha,N+3))):
> E1:=subs([seq(((D@@i)(f))(alpha) = 0,i=1..m-1),f(alpha)=0,x=e[n]+alpha],T1):
> g1 :=(convert(simplify(series((E1,e[n]=0,N))),polynom));

thanks. I played around, and had problems implementing your ideas for one of the systems I'm interested in.I don't see a difference between this and what you had advised me on, but it gets an error.

any idea why?
or how to fix it?

thing1 := diff(B[1](t), t) = piecewise(t <= 500, 0.3e-2-(63/10000)*B[1](t)-(3/500)*B[2](t), -(3/10000)*B[1](t)):
thing2 := diff(B[1](t), t) = piecewise(t <= 500, 0.1e-1-(1/50)*B[1](t)-(13/625)*B[2](t), -(1/1250)*B[2](t)):
sol := dsolve({thing1, thing2, B[1](0) = 0, B[2](0) = 0}, {B[1](t), B[2](t)}, numeric, output = listprocedure); plots:-odeplot(sol, [B[1](t), B[2](t)], t = 450 .. 550);

Error, (in dsolve/numeric/DAE/explicit) unable to obtain the standard form of the DAE system due to the presence of leading dependent variables/derivatives in the piecewise: piecewise(t <= 500, 1/100-(1/50)*B[1](t)-(13/625)*B[2](t), -(1/1250)*B[2](t))-piecewise(t <= 500, 3/1000-(63/10000)*B[1](t)-(3/500)*B[2](t), -(3/10000)*B[1](t))
Error, (in plots/odeplot) curve is not fully specified in terms of the ODE solution, found additional unknowns {B[1](t), B[2](t)}

how to do differentiation of an ideal in maple?

availables variables : a,b,c

case 1 : all are independent variebles, a,b,c

case 2 : only one independent variable, a

case 3: only one dependent variable a

i find this, but i do not know respect to which variable when differentiate an ideal which has 3 variables and 3 equations

http://www.maplesoft.com/support/help/maple/view.aspx?path=DifferentialAlgebra%2fTools%2fDifferentiate

I try to repeat lines (25)-(28) at

http://www.maplesoft.com/support/help/maple/view.aspx?path=Physics%2fTrace#commentform

I use Maple 14. However, instead of (28) I get the following result:

It means that Maple 14 does not perceive p_\mu, k_\nu and m as scalar quantities. I would like to ask how to define these variables correctly.

Thank you in advance!

hi.please help me for solve this equations

thanks...

Tur.mw

Non dimensionalisation is a vary common task, and I was suprised that I couldn't find a maple tool to automate it . Has anyone developed their own package for it?

I want to automatically do it to the system equations for some Dynamical systems to make some of the other processing I do with them easier.

I was hoping to start with somehting in the form of 

Diff(x[1],t)=f[1](p[1]....p[n],x[1]...x[m])

...

Diff(x[m],t)=f[m](p[1]....p[n],x[1]...x[m])

where each f[i] is some kind of quotient of multivariate polynomials in the variables and parameters:
and end up with something like

Diff(y[1],s)=f[1](q[1]....q[p],y[1]...y[m])

...

Diff(y[m],s)=f[m](q[1]....q[p],y[1]...y[m])

where p<n